Assuming the expression for the pressure exerted by the gas on the walls of the container, it can be shown that pressure is

Options

A. `[1/3]^(rd)` kinetic energy per unit volume of the gas
B. `[2/3]^(rd)` kinetic energy per unit volume of the gas
C. `[3/4]^(rd)` kinetic energy per unit volume of the gas
D. `3/2xx` kinetic energy per unit volume of the gas

Answer

B

Explanation

K.E. per unit volume of a gas = `3/2P`
`thereforeP=2/3` (K.E. per unit volume of the gas)