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At what temperature is the K.E. Of a gas...

At what temperature is the `K.E`. Of a gas molecules half that of its value at `27^(@)C`

A

`135^(@)C`

B

`150^(@)C`

C

`150K

D

300K

Text Solution

Verified by Experts

The correct Answer is:
C
Temperature `prop` K.E.
`E_(2)/E_(1)=T_(2)/T_(1)" "therefore1/2=T_(2)/300" "thereforeT_(2)=150K`
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