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100g of water is heated from 30^@C to 50...

100g of water is heated from `30^@C to 50^@C`. Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is `4184J//kg//K`):

A

4.2 KJ

B

8.4 kJ

C

84 kJ

D

2.1 kJ

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaQ=DeltaU+DeltaW`
In this case, `DeltaW` = 0 as no external work is done,
`DeltaQ=DeltaU`
But `DeltaQ=msd theta`
`=100xx10^(-3)xx4184xx(50-30)`
`=4184xx2=8368=8.368kJ=8.4kJ`
Thus `DeltaQ=DeltaU=8.4 kJ`
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