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The wavelength of maximum energy release...

The wavelength of maximum energy released during an atomic axplosion was `2.93xx10^(-10)m`. Given that Wien's constant is `2.93xx10^(-3)m-K`, the maximum temperature attained must be of the order of

A

`10^(3)`K

B

`10^(5)`K

C

`10^(7)`K

D

`10^(-10)`K

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda_(m)T=b`
`thereforeT=b/lamda_(m)=(2.93xx10^(-3))/(2.93xx10^(-10))`
`thereforeT=10^(7)K`
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