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A slit of width a is illuminiated by whi...

A slit of width a is illuminiated by white light. The first diffraction minimum for light of `lamda=6500 `Å is formed at `theta=30^(@)`, then the width (a) of the slit is

A

`6.5xx10^(-5)m`

B

`13xx10^(-6)m`

C

`1.3mum`

D

`2.6xx10^(-5)m`

Text Solution

Verified by Experts

The correct Answer is:
C
`asintheta =lamda" "therefore a=(lamda)/(sintheta)`
`=(6500xx10^(-10))/(1//2)=1.3xx10^(-6)m=1.3mum`
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