Four particles each of mass 'm' are placed at the four vertices of a square 'a' .Find net force on any one the particle.

Explanation

`F_(R)=sqrt(2)F+F'=(sqrt(2)Gm^(2))/(a^(2))+(Gm^(2))/(2a^(2))`
`F_(R)=(Gm^(2))/(a^(2))(sqrt(2)+1/2)` along the diagonals towards the opposite corner.