For particles of equal masses M that move along a circle of radius R under the action of their mutual gravitational attraction. Find the speed of each particle.

Explanation

in this case, the particles maintain gravitational force of attraction diametrically. The gravitational force one of the particles must be equal to the necessary centripetal force
`(mV^(2))/r=(Gmm)/((2r)^(2))rArr V=sqrt((Gm)/(4r))`