Find the percentage decrease in the weight of the body when taken to a depth of `32 km` below the surface of earth. Radius of the earth is `6400 km`.

Explanation

Weight of the body at a depth `d` is `mg'=mg(1-d/R)`
`%` decreases in weight `=(mg-mg')/(mg)xx100`
`=d/Rxx100=32/6400xx100=0.5%`