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A particle is fired vertically upward fom earth's surface and it goes up to a maximum height of 6400 km. find the initial speed of particle.

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`TE.` on the surface of the earth
`=T.E.` at the highest point
`1/2mV^(2)-(GMm)/R=0-(GMm)/(R+h)`
`rArr 1/2mV^(2)=(mgh)/([1+h/R])` given, `h=R=6400 Km`
So, `V^(2)=ghrArr V=sqrt(gh)`
`rArr V=sqrt(10xx6400xx10^(3))=8Km//d`
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NARAYNA-GRAVITATION-EXERCISE -IV
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