When projectile attains escape velocity,...

When projectile attains escape velocity, then on the surface of planet, its

`KEgtPE`

`PEgtKE`

`KE=PE`

`KE=2PE`

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Neglecting air resistance, a 1.0-kg projectile has an escape velocity of about 11km/s at the surface of Earth. The corresponding escape velocity for a 2.0 kg projectile is:

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The escape velocity from the surface of earth is V_(e) . The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be

A planet has mass equal to mass of the earth but radius one fourth of radius of the earth . Then escape velocity at the surface of this planet will be

sqrt((GM)/(R+h)) : critical velocity of a satellite at height h from surface of planet : : ……………… : escape velocity on the surface of planet

If acceleration due to gravity on the surface of a planet is two times that on surface of earth and its radius is double that of earth. Then escape velocity from the surface of that planet in comparison to earth will be

The escape velocity from the earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of earth and same mass density is

The escape velocity from the Earth's surface is v . The escape velocity from the surface of another planet having a radius four time that of Earth and same mass density :

NARAYNA-GRAVITATION-C.U.Q

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