If there particles, each of mass `M`, are placed at the three corners of an equilibrium triangle of side, a the force exerted by this system on another particle of mass `M` placed (i) at the midpoint of side and (ii) at the centre of the triangle are, respectively.

Options

A. `0,(4GM^(2))/(3a^(2))`
B. `(4GM^(2))/(3a^(2)),0`
C. `(3GM^(2))/(a^(2)),(GM^(2))/(a^(2))`
D. `0,0`

Answer

B

Explanation

Find individual forces and calculate resultant Use `F=(Gm_(1)m_(2))/(R^(2))`