The acceleration due to gravity at the latitude `45^(@)` on the earth becomes zero if the angular velocity of rotation of the earth is

Options

A. `sqrt(2/(gR))`
B. `sqrt(2gR)`
C. `sqrt((2g)/R)`
D. `sqrt((5R)/2)`

Answer

C

Explanation

`0=g-Romega^(2)cos^(2)45^(@)rArr omega=sqrt((2g)/R)`