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If v(e) is the escape velocity of a body...

If `v_(e)` is the escape velocity of a body from a planet of mass 'M' and radius 'R`. Then the velocity of the satellite revolving at height 'h' from the surface of the planet will be

A

`v_(e)sqrt(R/(R+h))`

B

`v_(e)sqrt((2R)/(R+h))`

C

`v_(e)sqrt((R+h)/R)`

D

`v_(e)sqrt(R/(2(R+h)))`

Text Solution

Verified by Experts

The correct Answer is:
D

`v_(e)=sqrt((2GM)/R),v=sqrt((GM)/(R+h))`
`rArr v/(v_(e))=sqrt(R/(2(R+h)))rArr v=v_(e)sqrt(R/(2(R+h)))`
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