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The electric field intensity produced by...

The electric field intensity produced by the radiations coming from 100W bulbs at a 3m distance is E. The electric field intensity produced by the radiations coming from 50W bulb at the same distance is

A

`(E)/(2)`

B

`2E`

C

`(E)/(sqrt(2))`

D

`sqrt(2)E`

Text Solution

Verified by Experts

The correct Answer is:
C
We know that, `E_(0) prop sqrt(P_(av))`
`:. ((E_(0))_(1))/((E_(0))_(2))=sqrt(((P_(av))_(1))/((P_(av))_(2)))implies (E)/((E_(0))_(2))=sqrt((1000)/(50))`
`(E_(0))_(2)=E//sqrt(2)`
Now according to question,
`P'=50W`, `P=100W`
`:.` Putting these value in Eq. (`i`). we get
`(E')/(E)=(50)/(100)implies (E')/(E)=(1)/(2)impliesE'=(E)/(2)`
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