In an electromagnetic wave, the amplitud...

In an electromagnetic wave, the amplitude of electric firld is `1 V/m`. The frequency of wave is `5xx10^(14)Hz`. The wave is propagating along `z`-axis. The average energy density of electric field, in `"joule"//m^(3)`,will be

`1.1xx10^(-11)`

`2.2xx10^(-12)`

`3.3xx10^(-13)`

`4.4xx10^(-14)`

Text Solution

Verified by Experts

The correct Answer is:

`(V_(av))_(E)=(1)/(4)epsilon_(0)E_(max)^(2)`

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