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The main scale of vernier callipers is d...

The main scale of vernier callipers is divided into `0.5mm` and its least count is `0.005 cm`. Then the number of divisions on vernier scale is

A

`10`

B

`20`

C

`30`

D

`40`

Text Solution

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The correct Answer is:
To find the number of divisions on the vernier scale, we can follow these steps: ### Step 1: Convert the least count to the same unit as the main scale The least count is given as `0.005 cm`. We need to convert this to millimeters (mm) since the main scale is in mm. \[ 0.005 \text{ cm} = 0.005 \times 10 \text{ mm} = 0.05 \text{ mm} \] ### Step 2: Identify the value of one main scale division (MSD) The main scale of the vernier callipers is divided into `0.5 mm`. Therefore, \[ \text{MSD} = 0.5 \text{ mm} \] ### Step 3: Use the formula for least count The least count (LC) of a vernier caliper is given by the formula: \[ \text{LC} = \frac{\text{MSD}}{n} \] where \( n \) is the number of divisions on the vernier scale. ### Step 4: Rearrange the formula to find \( n \) We can rearrange the formula to solve for \( n \): \[ n = \frac{\text{MSD}}{\text{LC}} \] ### Step 5: Substitute the values Now, we substitute the values we have: \[ n = \frac{0.5 \text{ mm}}{0.05 \text{ mm}} = 10 \] ### Conclusion The number of divisions on the vernier scale is \( n = 10 \). ---

To find the number of divisions on the vernier scale, we can follow these steps: ### Step 1: Convert the least count to the same unit as the main scale The least count is given as `0.005 cm`. We need to convert this to millimeters (mm) since the main scale is in mm. \[ 0.005 \text{ cm} = 0.005 \times 10 \text{ mm} = 0.05 \text{ mm} \] ...
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