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In a vernier callipers, smallest divisio...

In a vernier callipers, smallest division on the main scale is `1mm`, while the vernier scale have `20` divisions. When fixed jaw touches with movable jaw, zero of vernier scale lies on the right of the zero of the main scale and `15th` division of vernier scale coincides with any division of main scale. What is the type of zero error and its value?

A

positive, `0.75 mm`

B

negative, `0.75 mm`

C

positive, `0.15 mm`

D

negative, `0.15mm`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the vernier calipers and determine the type of zero error and its value, we can follow these steps: ### Step 1: Understand the Setup We have a vernier caliper where: - The smallest division on the main scale (MSD) is 1 mm. - The vernier scale (VS) has 20 divisions. ### Step 2: Calculate the Least Count (LC) The least count of the vernier calipers can be calculated using the formula: \[ \text{Least Count (LC)} = \text{Value of 1 MSD} - \text{Value of 1 VSD} \] Where VSD is the value of one division on the vernier scale. Since the vernier scale has 20 divisions that equal 1 mm: \[ \text{Value of 1 VSD} = \frac{1 \text{ mm}}{20} = 0.05 \text{ mm} \] Now, substituting the values: \[ \text{LC} = 1 \text{ mm} - 0.05 \text{ mm} = 0.95 \text{ mm} \] ### Step 3: Identify the Zero Error According to the problem, when the fixed jaw touches the movable jaw, the zero of the vernier scale lies to the right of the zero of the main scale. This indicates a positive zero error. ### Step 4: Determine the Zero Error Value The zero error can be calculated based on the division of the vernier scale that coincides with the main scale. The 15th division of the vernier scale coincides with a division of the main scale. Therefore, the zero error can be calculated as: \[ \text{Zero Error} = \text{(Vernier scale division that coincides)} \times \text{Least Count} \] Substituting the values: \[ \text{Zero Error} = 15 \times 0.05 \text{ mm} = 0.75 \text{ mm} \] ### Final Answer The type of zero error is **positive zero error**, and its value is **0.75 mm**. ---
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Knowledge Check

  • In a vernier callipers, one main scale division is x cm and n division of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is:

    A
    `((n - 1)/(n))x `
    B
    `((nx)/(n - 1))`
    C
    `x/n`
    D
    `(x/(n - 1))`
  • A vernier callipers used by student has 20 divisions in 1cm on main scale. 10 vernier divisions coincide with 9 main scale divisions. When jaws are closed, zero of main scale is on left of zero of vernier scale and 6th divisions of vernier scale coincides with any mains scale divisions. He placed a wooden cylinder in between the jaws and measure the length. The zero of vernier scale is on right of 3.2 cm mark of main division and 8th division of vernier scale with any main scale division. When he measures diameter of cylinder he finds that zero of vernier scale lies on right of 1.5 cm mark of main scale and 6th division of vernier scale coincides with any main scale division. Least count and zero error of vernier callipers are

    A
    `0.05cm`, `+0.3cm`
    B
    `0.05mm`, `-0.3mm`
    C
    `0.005cm`, `+0.03cm`
    D
    `0.05cm`, `-0.3cm`
  • In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-

    A
    `((n-1)/(n))x`
    B
    `(nx)/((n-1))`
    C
    `(x)/(n) `
    D
    `(x)/((n-1))`
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