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1 cm on the main scale of a vernier call...

`1 cm` on the main scale of a vernier callipers is divided into `10 equal` parts. If `10` divisions of vernier coincide with `8` small divisions of main scale, then the least count of the calliper is.

A

`0.01 cm`

B

`0.02 cm`

C

`0.05 cm`

D

`0.005 cm`

Text Solution

Verified by Experts

The correct Answer is:
B

`10VSD=8MSD`
`1VSD=0.8MSD`
Now `LC=1MSD-1VSD`
`=1MSD-0.8MSD`
`0.2MSD=0.2xx(1)/(10)cm`
`=0.02cm`.
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