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Pitch of the screw gauge is 0.5mm. Its h...

Pitch of the screw gauge is `0.5mm`. Its head scale contains `50` divisions. The least count of it is

A

`0.01mm`

B

`0.1mm`

C

`0.25mm`

D

`0.02mm`

Text Solution

Verified by Experts

The correct Answer is:
A

`LC=(0.5)/(50)`, `=(5)/(500)=0.01mm`
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Knowledge Check

  • In a screw gauge, the main scale has divisions in millimetre and circular scale has 50 divisions. The least count of screw gauge is

    A
    `2` microns
    B
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    D
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    B
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    C
    50
    D
    None of these
  • Assertion A : If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm. Reason R : Least Count = ("Pitch")/("Total divisionson circular scale") In the light of the above statements, choose the most appropriate answer from the options given below :

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    A is not correct but R is correct.
    B
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