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The circular scale of a screw gauge has ...

The circular scale of a screw gauge has `200` divisions. When it is given `4` complete rotations, it moves through `2mm`. The least count of the screw gauge is

A

`0.25xx10^(-2)cm`

B

`0.25xx10^(-3)cm`

C

`0.001cm`

D

`0.001mm`

Text Solution

Verified by Experts

The correct Answer is:
B
`LC=("pitch of the screw")/("number of circular scale divisions")`
`=(2)/(4(200))=0.25xx10^(-3)cm`
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