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An electric heater of power 150W is imme...

An electric heater of power `150W` is immersed in `0.75kg` of ice at `0^(@)C` in a lagged container of negligible heat capacity. The temperature remains constant for `27.5` minutes and then rises to `40.0^(@)C` in further `14 minutes`. Calculate the specific heat capacity of water.

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The correct Answer is:
A
Let `S` be the specific heat capacity of water heat taken by water at `0^(@)C` to rise it to `40^(@)C`.
`=msxxDelta t=0.75xxSxx(40-0)=30 s J kg`
Heat given by the heater in `14` mintues `=pxxt=150xx14xx60=126000 J` acc to principle method of mixtures heat taken by water `=` heat supplied by the water `30 s=12600`
`s=(126000)/(30)=4200 J Kg^(-1) K^(-1)`
or `4.2xx10^(3) J Kg^(-1) K^(-1)`.
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