Home
Class 12
PHYSICS
A, B, C and D are four resistance of 2Om...

`A`, `B`, `C` and `D` are four resistance of `2Omega`, `2Omega`, `2Omega` and `3Omega` respectivey. They are used to form a wheatstone bridge. The resistance `D` is short circuited with a resistance `R` in order to get the bridge balanced. The value of `R` will be

A

`4Omega`

B

`6Omega`

C

`8Omega`

D

`3Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
The bridge will be balanced when the shunted resistance of value `2Omega` i.e. `2=(3s)/(3+s)`
`s=6Omega`
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Level-v(Single answer)|23 Videos

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Multiple answer|6 Videos

  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Intergers type question|11 Videos

  • MAGNETISM

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

Four resistances of 3Omega, 3Omega, 3Omega and 4Omega respectively are used to form a Wheatstone bridge. The 4Omega resistance is short circuited with a resistance R in order to get bridge balanced. The value of R will be

Four resistors P, Q, R and S having resistances 3Omega,3Omega,4Omega and 6Omega respectively, are arranged to form a Wheatstone's bridge. The value of the resistance with which S must be shunted in order to balance the bridge is

Four resistances of 16 Omega , 12 Omega , 4 Omega and 9 Omega respectively are connected in cycle order so from a Wheatstone bridge. Calculate the resistance in be connected in parallel with 9 Omega resistance to balance the bridge.

Four resistence of 10 Omega, 60Omega,100Omega and 200Omega , respectively taken in order are used to form a Wheatstone's bridge . A 15 V battery is connected to the ends of a 200Omega resistance, the current through it will be

Four resistances 1Omega, 2Omega, 2 Omega, and 4 Omega are connected so as to form a Wheatstone's network. The cell of e.m.f. 2V is connected between its opposite points. The total current of bridge is

Four resistances 6Omega,6Omega,6Omega and 18Omega form a Wheatstone bridge. Find the resistance which connected across the 18Omega resistance will balance the network.

Four resistances 3Omega, 6Omega, 4Omega , and 12Omega are connected so as to form Wheatstone's network. Shunt needed across 12Omega resistor to balance the bridge is

Four resistances 10, 10 , 10 and 15 Omega are connected so as to form Wheatstone's bridge. The resistance connected across 15 Omega resistance to balance the bridge is