Home
Class 12
PHYSICS
Assertion (A): In Ohm's law experiment, ...

Assertion (A): In Ohm's law experiment, the reading of voltmenter and ammeter are `13.5V` and `0.40A` respectively, then the measured computed value of `R` is `33.75Omega` upto correct `SD`'s
Reason(R ): The reliability in computed value can not be more than the reliability in measured values.

A

If both assertion and reason are true and the reason is the correct explantion of the assertion.

B

If both assertion and reason are true and the reason is not the correct explantion of the assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true.

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Level-v(Single answer)|23 Videos

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Multiple answer|6 Videos

  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Intergers type question|11 Videos

  • MAGNETISM

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

In the adjoining circuit diagram, the readings of ammeter and voltmeter are 2 A and 120 V, respectively. If the value of R is 75Omega , then the voltmeter resistance will be

In Ohm's law experimental verification, the reading of voltage and resistance are (120 pm 5)V " and "(2 pm 0.1)Omega respectively. What is the percentage error in the value of current obtained?

For the adjoining circuit diagram, the readings of ammeter and voltmeter are 2A and 120 V respectively. If the value of R is 75 Omega , then the voltmeter resistance will be

In given figure an ammeter reads 5 A and voltmeter reads 40 V. The actual value of resistance R is

Assertion(A): In Ohm's law experiment potential drop across a resistance wire was measured as 5.0V and current was measured as 2.00A . The maximum permissible error in resistance is +-25% Reason(R ): In experiment of assertion the least count of ammeter is 0.01A .

In the circuit shown below, the ammeter A reads 5 A and the voltmeter V reads 20 V The correct value of resistance R is

In the adjacent circuit the ammeter reads 5.0 A and voltmeter reads 20V. The value of resistance R is

Consider the two circuits P and Q, shown below, which are used 20 measure the unknown resistance R. In each case, the resistance is estimated by using Ohm's law R_("est" = V // I , Where V and I are the readings of the voltmeter and the ammeter respectively. The meter resistances, R_(v) and R_(A) are such that R_(A) ltlt R ltlt R_(v) . The internal resistance of the battery may be ignored. The absolute error in the estimate of the resistance is denoted by deltaR = |R = R_("est")| .

The value of resistance of an unknown resistor is calculated using the formula R = V//I where V and I are the readings of the voltmeter and the ammeter, respectivley. Consider the circuits below. The internal resistances of the voltmeter and the ammeter (R_V and R_G, respectively) are finite and nonzero. , Let R_(A) and R_(B) be the calculated values in the two cases A and B , respectively. If the resistance of voltmeter is R_(V) = 1k Omega and the percentage error in the measurement of R (the value of R is nearly 10 Omega )is