Home
Class 12
PHYSICS
In a potentiometer experiment the balanc...

In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of `2Omega`, the balancing length becomes 120 cm.The internal resistance of the cell is

A

`2Omega`

B

`4Omega`

C

`0.5Omega`

D

`1Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`l_(1)=240cm`, `l_(2)=120cm`, `R=2 Omega`, `r=?`
`r=((l_(1)-l_(2))/(l_(2)))R=((240-120)/(120))xx2=2Omega`
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Level-v(Single answer)|23 Videos

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Multiple answer|6 Videos

  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Intergers type question|11 Videos

  • MAGNETISM

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

In a potentiometer the balancing with a cell is at length of 220cm. On shunting the cell with a resistance of 3Omega balance length becomes 130cm. What is the internal resistance of this cell.

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In potentiometer experiment, a cell is balanced by length 120cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

In a potentiometer experiment, the balancing length with a cell is 560cm. When an external resistance of 10ohms is connected in parallel to the cell the balancing length changs by 60cm. The internal resistance of the cell in ohm is

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10Omega is connected in parallel to the cell, the balancing length changes by 60 cm. Find the internal resistance of the cell.

It is observed in a potentiometer experiment that no current passes through the galvanometer, when the terminals of the potentiometer, wire. On shunting the cell by a 2Omega resistance, the balancing length is reduced to half. The internal resistance of the cell is:-

The emf of cell is balanced by balancing length 450 cm . When the resistance of 10 Omega is connected across the cell, balancing length changes by 100 cm. The internal resistance of a cell is

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is