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In a potentiometer whose wire resistance...

In a potentiometer whose wire resistance is `10Omega`. The potential fall per `cm` is `V "volts"` is reduced to `(V)/(4)"volt"//cm`. The resistance that must be connected in series with the potentiometer wire is

A

`40Omega`

B

`30Omega`

C

`20Omega`

D

`10Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
`(V)/((V)/(4))=(R^(1))/(10)implies R^(1)=40Omega`
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