Home
Class 12
PHYSICS
The potential gradients on the potentiom...

The potential gradients on the potentiometer wire are `V_(1)` and `V_(2)` with an ideal cell and a real cell of same emf in the primary circuit, then

A

`V_(1)=V_(2)`

B

`V_(1)gtV_(2)`

C

`V_(1) lt V_(2)`

D

`V_(1) le V_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Level-v(Single answer)|23 Videos

  • EXPERIMENTAL PHYSICS

    NARAYNA|Exercise Multiple answer|6 Videos

  • ELECTROSTATICS AND GAUSS LAW

    NARAYNA|Exercise Intergers type question|11 Videos

  • MAGNETISM

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

The balancing length on a potentiometer wire with a cell of emf 2V and internal resistance 1Omega connected in the secondary circuit with no load is 200cm . If a resistor of 19Omega is connected parallel to the cell, the balancing length

Potentiometer wire PQ of 1m length is connected to a standerd cell E_(1) . Another cell, E_(2) of emf 1.02 V is connected with a resistance r and a switch S open, null position is obtained at a distance of 51 cm from P Calculate (i) potential gradient of the potentiometer wire and (ii) emf of the cell E_(1) (iii) when swich S closed will mull point move toward P or toward Q ? Given resion for your answer ?

is made of uniform material and cross-sectional area, and it has uniform resistance per unit length. The potential gradient depends upon the current in the wire. A potentiometer with a cell of emf 2 V and internal resistance 0.4 Omega is used across the wire AB . A standard cadmium cell of emf 1.02 V gives a balance point at 66 cm length of wire. The standard cell is then replaced by a cell of unknows emf e (internal resistance r ), and the balance. Point found similarly turns out to be 88 cm length of the wire. The length of potentiometer wire AB is 1 m . The reading of the potentiometer, if a 4V battery is used instead of e is

A potentiometer is an ideal voltmeter since a voltmeter draws some current through the circuit while potentiometer needs no current to work. A potentiometer works on the principle of emf comparison. In working condition, a constant currant flows throughout the wire of a potentiometer is made of uniform material and cross-sectional area, and it has uniform resistance per unit length. The potential gradient depends upon the current in the wire. A potentiometer with a cell of emf 2 V and internal resistance 0.4 Omega is used across the wire AB . A standard cadmium cell of emf 1.02 V gives a balance point at 66 cm length of wire. The standard cell is then replaced by a cell of unknows emf e (internal resistance r ), and the balance. Point found similarly turns out to be 88 cm length of the wire. The length of potentiometer wire AB is 1 m . The value of e is

is made of uniform material and cross-sectional area, and it has uniform resistance per unit length. The potential gradient depends upon the current in the wire. A potentiometer with a cell of emf 2 V and internal resistance 0.4 Omega is used across the wire AB . A standard cadmium cell of emf 1.02 V gives a balance point at 66 cm length of wire. The standard cell is then replaced by a cell of unknows emf e (internal resistance r ), and the balance. Point found similarly turns out to be 88 cm length of the wire. The length of potentiometer wire AB is 1 m . If the resistance is connected across the cell e , the balancing length will

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

A 10 wire potentiometer has first five wires of cross sectional radius r and next five wires of radius 2r . The wires are uniform and made of same material. An ideal cell of emf 2 V is connected across the potentiometer wire. What length of the potentiometer wire will balance the emf of– (a) a Daniell cell (emf = 1.0 V) (b) a Lechlanche cell (emf = 1.5 V) (c) a cell of emf 1.8 V ? Length of each wire is 100 cm.

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

The balancing length of a potentiometer wire is 220cm when a cell of emf 1.1v is used in the secondary circuit.If it is replaced by a cell of emf 2.5v the balancing length becomes