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A prism of refractive index m and angle ...

A prism of refractive index `m` and angle `A` is placed in the minimum deviation position. If the angle of minimum deviation is `A`, then the value of `A` in terms of `m` is

A

`sin^(-1)[(mu)/(2)]`

B

`sin^(-1)[(sqrt(mu^(2)-1))/(2)]`

C

`2cos^(-1)[(mu)/(2)]`

D

`cos^(-1)[(mu)/(2)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`mu=sin((2A)/(2))/(sin((A)/(2)))`
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