In a screw gauge, the zero of mainscale ...

In a screw gauge, the zero of mainscale coincides with fifth division of circular scale in figure (i). The circular division of screw gauge are `50`. It moves `0.5 mm` on main scale In one rotation. The diameter of the ball in figure (ii) is

`2.25mm`

`2.20mm`

`1.20mm`

`1.25mm`

Text Solution

Verified by Experts

The correct Answer is:

`L.C=1MSR-1VSR=a-(n)/(n+1)a=(a)/(n+1)`

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