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Calcualte the volume of 0.324 M aq. H(2)...

Calcualte the volume of `0.324 M aq`. `H_(2) SO_(4)` required to react completelty with `2.9792g` of `Na_(2) CO_(3)`.

A

`3.81 mL`

B

`81.3 mL`

C

`78.6 mL`

D

`68.7 L`

Text Solution

Verified by Experts

The correct Answer is:
B
Balanced equation
`underset(1 mol) (H_(2) SO_(4)) + underset(106.0g) underset(1 mol)(Na_(2) CO_(3)) rarr underset(1 mol) (Na_(2) CO_(4)) + underset(1 mol) (CO_(2)) + underset(1 mol) (H_(2) O)`
tells us that 1 mol `H_(2) SO_(4)` reacts complelety with 1 mol `Na_(2) CO_(3)`, Now follow the sequence
`g Na_(2) CO_(3) rarr mol Na_(2) CO_(3) rarr mol H_(2) SO_(4) rarr` Vol. `H_(2) SO_(4)`
`? L H_(2) SO_(4) = 2.792g Na_(2) CO_(3) xx (1 mol Na_(2) CO_(3))/(106.0g Na_(2) CO_(3))`
`xx (1 mol H_(2) SO_(4))/(1 mol Na_(2) CO_(3)) xx (1L H_(2) SO_(4))/(0.324 mol H_(2) SO_(4))`
`= 0.0813L H_(2) SO_(4) = 81.3 mL H_(2) SO_(4)`
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