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An oxide of iodine (I = 127 atoms) cont...

An oxide of iodine `(I = 127` atoms) contains `42.3g` of idonie and `8g` of oxygen. Its formula could be

A

`I_(2)O_(5)`

B

`I_(2)O_(3)`

C

`I_(2)O_(7)`

D

`I_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
B
Find the ratio of moles of `I` and O.
`n_(1) : n_(O) = (42.3)/(127) , (8)/(16) = 0.33: 0.500 = (0.333)/(0.333) , (0.500)/(0.333)`
`= 1: 1.50 = 2:3`
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