`10g` of a piece of martbnel `(50%` pure) was into excess of dilute `HCl` acid. When the reaction was complte,.........of `CO_(2)` was obtained at `STP`

Options

A. `22.4L`
B. `5.6L`
C. `1.12L`
D. `7.4L`

Answer

C

Explanation

`CaCO_(3)(s) + 2HCl(aq.) rarr CaCl_(2)(aq.) + H_(2)O(l) + CO_(2)(g)`
According to the equation,
`100g CaCO_(3)` releases `22.4L CO_(2)`
`:. 5g(50% "of" 10g)` will relases `1.12 L CO_(2)`