A container contains `0.32g` of `O_(2)` and the same volume of an unknown gas at the same `T` and `P` weighing `0.26g`. If the gas obtain only `C` and `H` in the ratio `1 : 1` its molecular formula will be

Options

A. `C_(4) H_(4)`
B. `C_(2) H_(2)`
C. `C_(6) H_(6)`
D. `C_(10) H_(10)`

Answer

B

Explanation

According to Avogadro's law equal volumes contain equal number of moles. Thus, moles of unknown gas are equal to moles of `O_(2)` i.e., `0.32//32 = 0.01`. The molar mass of gas is `("mass"//n) = 26g`