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If 13.1g of Na(2) SO(4) XH(2)O contains ...

If `13.1g` of `Na_(2) SO_(4) XH_(2)O` contains `6g` of `H_(2)O`, the value of `X` is

A

`10`

B

`5`

C

`3`

D

`7`

Text Solution

Verified by Experts

The correct Answer is:
D
According to formula, 1 mol `Na_(2) SO_(4) (142g)` always combines with `X` moles `H_(2)O (18X g)`. According to data, mass of `Na_(2) SO_(4) = (13.1 - 6)g = 7.1g`. In a compound the ratio of mass is always fixed.
Thus, `(.^(m)Na_(2)SO_(4))/(.^(m)H_(2)O) = (142g)/(18Xg) = (7.1)/(6g)`
`:. X = ((42xx6))/((18xx7.1)) = (852)/(127.8) = 6.66 ~~ 7`
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