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Two metallic oxides contain 27.6% and 30...

Two metallic oxides contain `27.6%` and `30%` oxygen, respectively. If the formula of the second oxide is `M_(2)O_(3)`, that of the first will be

A

`M_(3) O_(4)`

B

`M_(2) O_(5)`

C

`MO_(3)`

D

`M_(2) O`

Text Solution

Verified by Experts

The correct Answer is:
A
In `M_(2) O_(3)`, 30 parts of `O` combine with 70 (parts of `M`. Thus, 70 parts of `M` in `M_(2)O` correspond to 2 atoms of `M`. In first oxide, `72.4` parts will correspond to `(2)/(70) xx 74.7 = 2.07 M` atoms. 30 parts of `O` in `M_(2) O_(3)` corrrespond to 3 atom of `O`. In first oxide, 27.6 parts of `O` will correspond to `(3)/(30) xx 27.6 = 2.76 O` atoms. Ratio of `M` to `O` in the first oxide `= 2.07 : 2.76 = (2.07)/(2.07) = (2.76)/(2.07) = 1 : 1 : 33 = 3 : 4`
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Knowledge Check

  • Empirical formula is the simplest formula of the compound which gives the atomic ratio of various elements present in one molecule of the compound. However, the molecular formula of the compound gives the number of atoms of various elements present in one molecule of the compound. Molecular formula=(Empirical formula) xxn n=("Molecular mass")/("Empirical formula mass") A compound may have same empirical and molecular formulae Both these formulae are calculated by using percentage composition of constituent elements. Two metallic oxides contain 27.6% and 30% oxygen respectively. if the formulae of first oxide is M_(3)O_(4) , that of second will be:

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