The ionization potential for hydrogen atom is `13.6 eV`, the ionization potential for `He^(+)` is

Options

A. `24.5 V`
B. `6.8 V`
C. `54.4 V`
D. `13.6 V`

Answer

C

Explanation

Ionization potentila `= ("Ionization enegry"(eV))/(e)`
where `e` is the charge on electron.
According to Bohr's theory,
Ionization enegry `(eV) =- Z^(2)E_(1)`
For `He^(+)`,
`IE(eV) =- (2)^(2) (-13.6eV)`
`= 54.4 eV`
Note that for `H` atom, `IE` is `13.6eV`, thus, `E_(1) =- 13.6eV` as `Z = 1` for `H` atom.
Finally, Ionization potential `= (54.4eV)/(e) = 54.4V`