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A quantity of 2 mol of NH(3) occupies 5L...

A quantity of 2 mol of `NH_(3)` occupies 5L at `27^(@)C`. Calculate the pressure of the gas using the van der Waals equation if `a = 4.17 "atm "L^(2)" mol"^(-2)` and `b = 0.3711 L "mol"^(-1)`.

A

`9.2 atm`

B

`9.74 atm`

C

`10.33 atm`

D

`9.33 atm`

Text Solution

Verified by Experts

The correct Answer is:
D
According to van der Waals equations , we have
`(p + (an^(2))/(V^(2))) (V - nb) = nRT`
or `p = (nRT)/(V _ nb) - (an^(2))/(V^(2))`
`= ((2 "mol")(0.821 (L "atm")/(L "mol"))(300 K))/(5 L - (2"mol") (0.03711 L "mol"^(-1)))- ((1.17 ("atm" L^(2))/("mol"^(2)))(2 "mol")^(2))/((5 L)^(2))`
`= (10 "atm") - (0.66 "atm") = 9.33`
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