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The oxidation states of the most electro...

The oxidation states of the most electronegative element in the products of the reaction between `BaO_2` with dilute `H_2SO_4` are

A

`-2` and 0

B

`-1` and `-2`

C

0 and `-1`

D

`-2` and `+1`

Text Solution

Verified by Experts

The correct Answer is:
B
`BaO_(2)+H_(2)SO_(4) rarr BaSO_(4) + H_(2)O_(2)`
Oxygen, the most electronegative element, has the oxidation state of ` -1` in hydrogen peroxide `(H_2O_2)` and ` -2` in barium sulphate `(BaSO_4)`.
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