The intermediate formed during the addition of HCl to propene in the presence of a peroxide is

Options

A. `CH_(3)overset(+)(C )HCH_(3)`
B. `ClCH_(2)overset(.)(C )HCH_(3)`
C. `CH_(3)underset(Cl)underset(|)(CH)CH_(2)`
D. `CH_(3)CH_(2)CH_(2)`

Explanation

To determine the intermediate formed during the addition of HCl to propene in the presence of a peroxide, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction**:
The reaction involves the addition of HCl to propene (C3H6). Propene is an alkene with a double bond between the first and second carbon atoms.

2. **Identifying the Role of Peroxide**:
It is important to note that the presence of peroxide affects the mechanism of the reaction. While it is commonly known that peroxides lead to anti-Markovnikov addition in the case of HBr, this does not apply to HCl. Thus, we will follow the Markovnikov rule for HCl addition.

3. **Formation of Carbocation**:
When HCl adds to propene, the double bond breaks, and a carbocation is formed. The hydrogen (H) from HCl will add to the carbon atom that can lead to the more stable carbocation. In propene, this would typically be the first carbon (C1) because it leads to the formation of a secondary carbocation at C2, which is more stable than a primary carbocation.

4. **Drawing the Intermediate**:
After the addition of HCl, the intermediate formed is a secondary carbocation. The structure of the carbocation can be represented as follows:
- The first carbon (C1) has a hydrogen atom attached from HCl.
- The second carbon (C2) carries a positive charge, making it a secondary carbocation.

5. **Conclusion**:
Therefore, the intermediate formed during the addition of HCl to propene in the presence of peroxide is a secondary carbocation.

### Final Answer:
The intermediate formed during the addition of HCl to propene in the presence of a peroxide is a secondary carbocation.

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