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Reduction potential for the following h ...

Reduction potential for the following h alf-cell reaction are
`Zn rarr Zn rarr Zn^(2+)+2e^(-),E_(Zn^(2+)//Zn)^(@) = -0.76V`
`Fe rarr Fe^(2+)+2e^(-),E_(Fe^(2+)//Fe)^(@) = -0.76V`
The emf for the cell reaction
`Fe^(2+)Zn rarr Zn^(2+)+Fe`
will be

A

`+0.32 V`

B

`-0.32 V`

C

`+1.20 V`

D

`-1.20 V`

Text Solution

Verified by Experts

The correct Answer is:
A
Electrode having the higher reduction potential acts as cathode while the one with lower reduction potential acts as anode. Thus,
`E_("cell")^(@) = E_(R)^(@)-E_(L)^(@)`
`= (-0.44 V)-(-0.76 V) = +0.32 V`
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