A hemispherical bowl just floats without sinking in a liquid of density `1.2xx10^(3)kg//m^(3)`. If outer diameter and the density of the bowl are `1m` and `2 xx 10^(4) kg//m^(3)` respectively, then the inner diameter of bowl will be

Options

A. 1.91 m
B. 0.5 m
C. 0.98 m
D. 1.75 m

Explanation

Let `d` the inner diameter weight fo displaced liquid`=` weight of the body `m^(1)g=mg`
Vol. of displaced. Liquid`xx` density of liquid `=` vol. of the body `xx` density of the body
`(4pi)/(3)((1)/(2))^(3)xx1.2xx10^(3)=(4pi)/(3)[((1)/(2))^(3)-((d)/(2))^(3)]xx2xx10^(4)`