A large open top container of negligible mass and uniform ross sectional area `A` has a small uniform cross sectional area `a` in its side wall near the bottom. The container is kept over a smooth horizontal floor and contains a liquid of density `rho` and mass `m_(0)`. Assuming that the liqudi starts flowing through the hole A the acceleration of the container will be

Options

A. `(2ag)/(A)`
B. `(ag)/(A)`
C. `(2Ag)/(a)`
D. `(Ag)/(a)`

Explanation

`F=ma^('),rhoav^(2)=ma^('),rhoa(2gh)=ma^(')`
`a^(')=(1rhoagh)/(m)=(2rhoagh)/(rhoAh)=(2ag)/(A)`