A glass plate of length 20 cm and breadth 0.2 cm just touches the water surface in a beaker. The surface tension of water is 72 dyne/cm. The weight of the glass plate is 25 g. The weight that must be placed in the right pan to counter pose the balance is

Options

A. 25 g
B. 28 g
C. 22 g
D. 21.3 g

Explanation

To solve the problem, we need to find the weight that must be placed in the right pan to balance the forces acting on the glass plate in the beaker of water. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Forces Acting on the Glass Plate
The forces acting on the glass plate include:
- The weight of the glass plate (W_plate)
- The upward force due to surface tension (F_surface_tension)

### Step 2: Calculate the Weight of the Glass Plate
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