A water drop is divided into eight equal droplets. The pressure difference between inner and outer sides of big drop is

Options

A. will be the same as for smaller droplet
B. will be half of the for smaller droplet
C. will be `(1)/(4)^(th)` of that for smaller droplet
D. will be twice of that for smaller droplet

Explanation

`P=(2T)/(R)`,
`(P_(1))/(P_(2))=(R_(2))/(R_(1))(because(4)/(3)piR^(3)=8xx(4)/(3)pir^(3)impliesR=2r)implies(P_("big"))/(P_("small"))=(r)/(R)`