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30 gms of water at 30^@C is in a beaker....

`30 gms` of water at `30^@C` is in a beaker. Which of the following, when added to water, will have greatest cooling effect ? (Specific heat of copper `= 0.1 cal//gm^@C`)

A

`100gm` of water at `10^@C`

B

`15 gm` of water at `0^@C`

C

`3 gm` of ice at `0^@C`

D

`18 gm` of copper at `0^@C`

Text Solution

Verified by Experts

The correct Answer is:
A
From principle of calorimetry ltbtgt (i) `mS_(w)(30 - theta_(1)) = m_(1)S_(w)(theta_(1)-10)`
(ii) `mS_(w)(30-theta_(2)) = m_(2)S_(w) (theta_(2)-0)`
(iii) `mS_(w)(30-theta_(3)) = m_(3)L_(ice) +m_(3)S_(w)(theta_(3)-0)`
(iv) `mS_(w)(30-theta_(4)) = m_(4)S_(cu) (theta_(4)-0)`
here `m_(1) = 100 g, m_(2) = 15 g, m_(3) = 3g, m_(4) = 18 g` above calculations will be show that `theta_(1)` is least.
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