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Ice at 0^@C is added to 200 g of water i...

Ice at `0^@C` is added to 200 g of water initially at `70^@C` in a vacuum flask. When 50 g of ice has been added and has all melted the temperature of the flask and contents is `40^@C`. When a further 80 g of ice has been added and has all melted the temperature of the whole becomes `10^@C`. Find the latent heat of fusion of ice.

A

`80 cal//gm`

B

`90 cal//gm`

C

`70 cal//gm`

D

`540 cal//gm`

Text Solution

Verified by Experts

The correct Answer is:
B
According to principle of calorimetry
`ML_(f) + MS Delta theta = (mS Delta theta)_(water) + (mS Delta theta)_(flask)`
`5L_(f)=400+3w`…(i), here `w = (ms)_(flask)`
Now the system contains `(200+50) gm` of water at `40^@C`, so when further `80 gm` of ice is added
`8 L_(f) = 670 + 3w` ....(ii)
from (i) & (ii) we get `L_(f)`.
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