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A stone is thrown horizontally with a ve...

A stone is thrown horizontally with a velocity of `10m//sec`. Find the radius of curvature of it’s trajectory at the end of `3 s` after motion began. `(g=10m//s^(2))`

A

`10sqrt10m`

B

`100sqrt10m`

C

`sqrt10m`

D

`100 m`

Text Solution

Verified by Experts

The correct Answer is:
A

Radius of curvature `r=v_(t)^(2)/(g sin alpha)`
`V=sqrt(v_(x)^(2)+v_(y)^(2))=10sqrt10`
`tan alpha=v_(x)/v_(y)=1/3, sin alpha=1/sqrt10`
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