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As shown in figure AB represents an infi...

As shown in figure `AB` represents an infinite wall tangential to a horizontal semi circular track.`O` is a point source of light on the ground at the centre of the circle. A block moves along the circular track with speed `v` starting from the point where the wall touches the circle. If the velocity and acceleration of shadow along the length of the wall is respectively `'V'` and `'a'` then,

A

`V=v cos"(vt)/R`

B

`V=v sec^(2)((vt)/R)`

C

`a=v^(2)/Rsec^(2)((vt)/R)tan((vt)/R)`

D

`a=(2v^(2))/Rsec^(2)((vt)/R)tan((vt)/R)`

Text Solution

Verified by Experts

The correct Answer is:
B, D


`"T"an theta=y/R,y=R tan theta`
`v=(dy)/(dt)=R sec^(2)theta(("d"theta)/(dt))=Romegasec^(2)theta`
`= v sec^(2)((vt)/R)`
acceleration of the shadow:
`a=(dv)/(dt)=(2v^(2))/Rsec^(2)((vt)/R)tan((vt)/R)`
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