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A particle P of mass m is attached to a ...

A particle `P` of mass `m` is attached to a vertical axis by two strings `AP` and `BP` of legth `l` each. The separation `AB=l`, rotates around the axis with an angular velocity `omega`. The tension in the two string are `T_(1)` and `T_(2)`. Then

A

`T_(1)=T_(2)`

B

`T_(1)+T_(2)=m omega^(2)l`

C

`T_(1)-T_(2)=2mg`

D

`BP` will remains taut only if `omega ge sqrt(2g//l)`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
`ABP` equilateral, `T(1),T_(2)` tensions along `PA` and `PB` respectively
`T_(1)cos 60=T_(2)cos 60+mg,T_(1)-T_(2)=2mg`
`T_(1)sin 60+T_(2)sin 60=g(l sin 60)omega^(2)`
`T_(1)+T_(2)=momega^(2)l`, if `T_(2)=0`
`T_(1)=2mg, rArr omega^(2)l=2g`
if `omegagesqrt((2g)/(l))` BP will be taut
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