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Two pendulum bobs of mass m and 2m colli...

Two pendulum bobs of mass `m` and `2m` collide elastically at the lowest point in their motion. If both the balls are releasd from height `H` above the lowest point,
Velocity of the bob of mass `m` just after collision is

A

`sqrt((2g H)/(3))`

B

`(5)/(3)sqrt(2gH)`

C

`sqrt(2gH)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`v_(1) = ((m_(1)-m_(2))/(m_(1)+m_(2)))u_(1)+(2m_(2))/(m_(1)+m_(2))u_(2)`
`v_(1) = ((m-m xx 2)/(m+2m))(-sqrt(2gH))+((4m)/(m+2m))sqrt(2gH)`
`= (5)/(3) sqrt(2gH)`
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