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Two pendulum bobs of masses m and 2m col...

Two pendulum bobs of masses m and 2m collide head on elastically at the lowest point in their motion. If both the balls are released from a height H above the lowest point, to what heights do they rise for the first time after collision?

A

`(25H)/(9)`

B

`(H)/(9)`

C

`(16 H)/(9)`

D

`(H)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`h_(1) = (v_(1)^(2))/(2g) = [(5)/(3)sqrt(2gH)]^(2)/(2g), h_(1) = (25)/(9)H`
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